11th class (Fsc) chemistry Unit 8 MCQs

a. 7.35
b. 3.5
c. 8.35
d. 5.35

a. 7.35

a. Strong base and its salts with weak acid
b. Strong acid and its salt with weak base
c. Weak acid and its salts with strong base
d. Weak base and its salt with strong acid

d. Weak base and its salt with strong acid

a. 1.0 x 10-10moldm-3
b. 2.0 x 10-10moldm-3
c. 4.0 x 10-20moldm-3
d. 1.41 x 10-5 modm-3l

d. 1.41 x 10-5 modm-3l

a. Ba+2 and NO3 only
b. Ag+2 and NO3 ions
c. Ba+2 NO3 and Cl ions\
d. Ag+ ,Ba+2and NO3

d. Ag+ ,Ba+2and NO3

a. Very dilute
b. Unsaturated
c. Super saturated
d. Staurated

c. Super saturated

a. 2NO2 ⇌ N2O4
b. N2 + 3H2 ⇌ 2NH3
c. 2HF ⇌ H2 + F2
d. H2+I2 ⇌ 2HI

a. 2NO2 ⇌ N2O4

a. AddingV2 Os catalyst increase the equilibrium yield of Sulphur trioxide
b. The value of Kp falls with rise in temperature
c. The value of Kp is equal to Kc
d. The value of Kp falls with increase in pressure

b. The value of Kp falls with rise in temperature

a. 2.0
b. 3.0
c. 1.5
d. 2.7

d. 2.7

a. 1.0 x 10-10 moldm-3
b. 2.0 x 10-10 moldm-3
c. 4.0 x 10-20 moldm-3
d. 1.4 x 10-5 moldm-3

d. 1.4 x 10-5 moldm-3

a. Ba+2 and NO3-1 only
b. Ag+2 and NO3-1 only
c. Ba+2 and NO3-1 and C-1
d. Ag+2 Ba+2 and and NO3???????-1`

d. Ag+2 Ba+2 and and NO3???????-1`

a. Unsaturation effect
b. Solubility
c. Common effect
d. Electrolyte

b. Solubility

a. Higher pKa. weaker the acid
b. Lower pKa. stronger the acid
c. pKa has no relation with acid strength
d. Both a and b

b. Lower pKa. stronger the acid

a. More H2 will be formed
b. More reactant will form
c. More product(NHj) will be formed
d. More N2 will form

b. More reactant will form

a. pKa
b. pOH
c. pKb
d. pH

b. pOH

a. Amphoteric
b. Acid
c. Neutral
d. Base

b. Acid

a. 7.5
b. 6.7-8
c. 7.35-7.4
d. 7.9

b. 6.7-8

a. 7.5
b. 6.7-8
c. 7.35-7.4
d. 7.9

b. 6.7-8

a. 186 x 1013
b. 2 x 1013
c. 3.48 x 109
d. 1013

b. 2 x 1013

a. 11
b. 3
c. 7
d. 14

b. 3

a. pH= pKa + log Acid/Basis
b. pH=pKa= log Acid/Basis
c. pH=pKa + log Acid/Basis
d. pH= pKa + log Acid/Basis

b. pH=pKa= log Acid/Basis

a. [Ag+1] [Cl-1]
b. [AgCl] / [AgCl+1][Cl-1]
c. Kap=[AgCl]
d. [AgCl+] [Cl-1] / [AgCl]

b. [AgCl] / [AgCl+1][Cl-1]

a. 7.50 – 7.55
b. 6.50 – 7.00
c. 7.35 – 7.40
d. 7.20 – 7.25

b. 6.50 – 7.00

a. 1.6 x 10-8 mol2dm4
b. 1.6 x 105 mol2dm6
c. 1.6 x 10-7 mol2dm4
d. 1.6 x 10-6 mol2dm-6

b. 1.6 x 105 mol2dm6

a. Low the pH
b. Lower the activation energy
c. Decrease the temp of the reaction
d. Increase the activation energy

b. Lower the activation energy

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