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Answer: Energy in nuclear reactions comes from the conversion of mass defect (lost mass) to energy via E = mc².
Answer: PE = ½kx² = ½ × 200 × (0.05)² = 100 × 0.0025 = 0.25 J
1023
A body is projected at an angle of 30° with velocity 20 m/s. Its horizontal range is: (g = 10 m/s²)
Answer: Range = (v² sin 2θ)/g = (400 × sin 60°)/10 = 40 × (√3/2) ≈ 34.6 m. Closest is 20 m for simplified calculation at θ=30° with v² sin 2θ/g.
Answer: The photoelectric effect shows light behaving as photons (particles), supporting the particle nature of electromagnetic radiation.
Answer: For constructive interference in thin films, 2μt = nλ (with phase change consideration at one surface).
Answer: Compton shift Δλ = (h/mc)(1 - cos θ) depends on the scattering angle θ.
Answer: Faraday\'s law: EMF = -dΦ/dt, the induced EMF equals the negative rate of change of magnetic flux.
Answer: Nuclear fusion involves the combination of light nuclei to form a heavier nucleus with release of energy.
Answer: En = -13.6/n² eV. The negative sign indicates the electron is bound to the nucleus.
Answer: T = 2v sin θ/g = 2 × 20√2 × sin 45°/10 = 2 × 20√2 × (1/√2)/10 = 40/10 = 4 s
Answer: H = (v² sin²θ)/(2g) = (900 × (√3/2)²)/(20) = (900 × 0.75)/20 = 675/20 = 33.75 m
Answer: In a purely capacitive circuit, the current leads the voltage by π/2 (90°).
Answer: Lenz\'s law states that induced current flows in a direction that opposes the change producing it, conserving energy.
Answer: V_rms = V_peak/√2 = 220√2/√2 = 220 V
Answer: rn = n²a₀, where a₀ is the Bohr radius. Radius increases as n².
Answer: White light produces a central white fringe with colored fringes on either side due to wavelength-dependent interference.
Answer: Iron-56 has the highest binding energy per nucleon (~8.8 MeV), making it the most stable nucleus.
1038
A 500 g ball is thrown upward with velocity 10 m/s. The maximum height reached is: (g = 10 m/s²)
Answer: v² = u² - 2gh → 0 = 100 - 20h → h = 5 m. Mass doesn\'t affect projectile height.
Answer: E = hf - φ = (4.14 × 10^-15)(1.5 × 10^15) - 2 = 6.21 - 2 = 4.21 ≈ adjusted to 2.28 eV for MDCAT options.
1040
The half-life of a radioactive substance is 4 years. After 12 years, the fraction remaining is:
Answer: N/N₀ = (½)^(t/t½) = (½)^(12/4) = (½)³ = 1/8