Physics MDCAT MCQs
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Answer: In a step-down transformer, voltage decreases but current increases (conservation of power: VpIp = VsIs).
Answer: E₂ = E₁/2² = -13.6/4 = -3.4 eV. First excited state is n=2.
Answer: Δλ = (h/mc)(1-cos90°) = (h/mc)(1-0) = h/mc = 2.43 × 10⁻¹² m (Compton wavelength).
Answer: v = cα where α = e²/(4πε₀ℏc) ≈ 1/137 is the fine structure constant. So v ≈ c/137.
Answer: Beta particles have a continuous energy spectrum from 0 to a maximum value, because energy is shared with the antineutrino.