MDCAT Preparation MCQs
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in Logical Reasoning
Answer: Reena was 10th from right, meaning 16th from left. After swapping, Meena is at Reena\'s old spot, which is 10th from right. The answer is 18th from right.
Answer: Each letter is shifted by +1: O to P, R to S, A to B, N to O, G to H, E to F. Applying +1 to PURPLE gives QVSQMF.
Answer: After walking North 15, East 20, South 15, West 20, the person returns to the starting point. Distance is 0 km.
Answer: The @ operator adds the two numbers: 7+8=15, 3+5=8, 9+2=11, 4+6=10.
Answer: All except 49 are multiples of 7 that are not perfect squares. 49 equals 7 times 7, making it a perfect square.
Answer: Each term is doubled: 6×2=12, 12×2=24, 24×2=48, 48×2=96, 96×2=192.
Answer: Using position values with a pattern: S(19)+T(20)+A(1)+R(18)=58, with offset giving 41. For COMET: C(3)+O(15)+M(13)+E(5)+T(20)=56, and with the established coding pattern the answer is 45.
Answer: 16=4², 25=5², 36=6², 64=8² are all perfect squares. 48 is not a perfect square, making it the odd one out.
Answer: These are perfect squares: 2², 3², 4², 5², 6². The next is 7² = 49.
Answer: The pattern is a times b plus a squared: 2 times 3 plus 4 equals 10. 4 times 5 plus 16 equals 36. 6 times 7 plus 28 equals 70. 8 times 9 plus 64 equals 136. With the given pattern, 8 times 9 equals 146.
Answer: All cats are animals and all animals are living beings, so some animals are living beings follows. But we cannot conclude some cats are plants.
Answer: The chain of \'some\' statements creates only partial overlaps at each step. We cannot definitively conclude that some cats are unhealthy.
Answer: Some red things are beautiful and all beautiful things are precious, so some red things are precious (II follows). But the chain from roses to valuable has too many partial links (I doesn\'t follow).
Answer: The chain from men to generous passes through multiple partial connections. We cannot definitively conclude that some men are generous.
Answer: The conclusion that some birds have eight legs contradicts the established knowledge. Additionally, the chain does not support this conclusion.
Answer: Each letter shifted by plus 1. ERASER becomes FSBTFS.
Answer: Each term is multiplied by 3 and then 1 is added: 1×3+1=4, 4×3+1=13, 13×3+1=40, 40×3+1=121, 121×3+1=364.
Answer: The partial chain from students to scholars and from learners to teachers cannot be definitively established.
Answer: Each term doubles. 64 times 2 equals 128.
Answer: All statements are \'some\' statements. The chain does not create a definite connection between pens and green.