Physics MDCAT

Mechanics, electricity & modern physics MCQs

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Physics

MDCAT Physics MCQs — mechanics, waves, electricity & modern physics

305 MCQs Page 14 of 16
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A. 1.097 × 10^7 m⁻¹
B. 6.674 × 10⁻¹¹ N·m²/kg²
C. 8.987 × 10^9 N·m²/C²
D. 9.109 × 10⁻³¹ kg
Answer: R = 1.097 × 10^7 m⁻¹ is the Rydberg constant used in the hydrogen spectral series formula.
A. Lyman series line
B. Balmer series line
C. Paschen series line
D. Brackett series line
Answer: Transitions to n=2 produce the Balmer series (visible light region).
A. 13.6 eV
B. 3.4 eV
C. 10.2 eV
D. 6.8 eV
Answer: ΔE = 13.6(1 - 1/4) = 13.6 × 3/4 = 10.2 eV
A. Parallel to the magnetic field
B. Perpendicular to the magnetic field
C. At 45° to the field
D. At 60° to the field
Answer: When the plane is parallel to the field, the area vector is perpendicular, giving maximum torque τ = M × B.
A. Frequency of AC voltage
B. Magnetic field and radius of dees
C. Only the mass of particle
D. Only the charge of particle
Answer: KE_max = q²B²R²/(2m), depending on magnetic field B and radius R of the dees.
A. Steady current
B. Change in current
C. Voltage
D. Resistance
Answer: Self-inductance produces a back EMF that opposes any change in current (Lenz\'s law applied to self-induction).
A. LI²
B. ½LI²
C. LI
D. ½LI
Answer: Energy stored in inductor = ½LI², analogous to energy stored in capacitor = ½CV².
A. 7 Ω
B. 1 Ω
C. 5 Ω
D. 12 Ω
Answer: Z = √(R² + XL²) = √(9 + 16) = √25 = 5 Ω
A.
B. 45°
C. 90°
D. 60°
Answer: tan φ = XC/R = 10/10 = 1 → φ = tan⁻¹(1) = 45°. Current leads voltage.
B. 1
C. 0.5
D. Infinity
Answer: At resonance, Z = R (minimum), so power factor cos φ = R/Z = 1. Circuit behaves as purely resistive.
A. 92
B. 143
C. 235
D. 327
Answer: Number of neutrons = Mass number - Atomic number = 235 - 92 = 143
A. Total energy released
B. Mass of products
C. Kinetic energy of products
D. Binding energy of products
Answer: Q-value = (mass of reactants - mass of products)c² = total energy released in the nuclear reaction.
A. Atoms move faster
B. Coulomb barrier must be overcome
C. Gravity increases
D. Neutrons are released
Answer: Nuclei must have enough kinetic energy to overcome the Coulomb repulsion between positively charged nuclei.
A. Parallel
B. Perpendicular to each other and to propagation
C. At 45° to each other
D. In the same direction
Answer: In EM waves, E and B fields are perpendicular to each other and both are perpendicular to the direction of wave propagation.
A. 3 × 10^8 m/s
B. 3 × 10^6 m/s
C. 3 × 10^10 m/s
D. 3 × 10^5 m/s
Answer: All electromagnetic waves travel at c = 3 × 10^8 m/s in vacuum.
A. Faraday
B. Maxwell
C. Ampere
D. Gauss
Answer: Maxwell introduced the concept of displacement current to make Ampere\'s law consistent for time-varying fields.
A. Amplitude only
B. Frequency only
C. Square of amplitude
D. Wavelength
Answer: Energy density u = ε₀E² = ε₀E₀² sin²(ωt-kx), proportional to the square of the amplitude.
A. Energy density
B. Energy flux density (power per unit area)
C. Magnetic flux
D. Electric flux
Answer: Poynting vector S = E × B/μ₀ represents the directional energy flux (power per unit area) of the EM wave.
A. Are accelerated
B. Hit a metal target
C. Are deflected by magnetic field
D. Combine with protons
Answer: X-rays are produced when high-speed electrons are suddenly decelerated upon striking a metal target.
A. 1.24 eV
B. 2.48 eV
C. 3.72 eV
D. 0.62 eV
Answer: φ = hc/λ₀ = 12400/5000 = 2.48 eV