Science Group

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Science Group

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A. Twice the threshold frequency
B. Half the threshold frequency
C. The threshold frequency
D. Three times the threshold frequency
Answer: At threshold frequency f₀, KE = hf₀ - φ = 0. The photon energy just equals the work function.
A. Speed of particle
B. Charge of particle
C. Both speed and radius
D. Mass of particle
Answer: T = 2πm/qB is independent of both speed and radius. It depends only on m, q, and B.
A. Faraday\'s law
B. Lenz\'s law
C. Ohm\'s law
D. Coulomb\'s law
Answer: Lenz\'s law gives the direction of induced current, while Faraday\'s law gives the magnitude of induced EMF.
A. T
B.
C.
D. T⁴
Answer: Stefan-Boltzmann law: E = σT⁴. Energy radiated is proportional to the fourth power of absolute temperature.
A. 1:1
B. 2:1
C. 1:2
D. 4:1
Answer: λ = h/√(2qVm). λp/λα = √(qα/qp) = √(4e/e) = 2. So ratio is 2:1.
A. h/mc
B. 2h/mc
C. h/(2mc)
D. Zero
Answer: Δλ = (h/mc)(1-cos90°) = (h/mc)(1-0) = h/mc = 2.43 × 10⁻¹² m (Compton wavelength).
A. Is fixed
B. Is continuous up to a maximum value
C. Depends on temperature
D. Is always zero
Answer: Beta particles have a continuous energy spectrum from 0 to a maximum value, because energy is shared with the antineutrino.
A. c/137
B. c
C. c/2
D. c/10
Answer: v = cα where α = e²/(4πε₀ℏc) ≈ 1/137 is the fine structure constant. So v ≈ c/137.
A. -3.4 eV
B. -6.8 eV
C. -1.51 eV
D. -27.2 eV
Answer: E₂ = E₁/2² = -13.6/4 = -3.4 eV. First excited state is n=2.
A. Less than primary
B. More than primary
C. Same as primary
D. Zero
Answer: In a step-down transformer, voltage decreases but current increases (conservation of power: VpIp = VsIs).
A. sp
B. sp2
C. sp3
D. sp3d
Answer: Carbon in CH4 forms four sigma bonds with no lone pairs, giving sp3 hybridization and tetrahedral geometry.
A. 6
B. 8
C. 14
D. 10
Answer: Carbon-14 has atomic number 6 (protons = 6) and mass number 14. Neutrons = 14 - 6 = 8.
A. Principal quantum number (n)
B. Azimuthal quantum number (l)
C. Magnetic quantum number (ml)
D. Spin quantum number (ms)
Answer: The azimuthal quantum number (l) determines the shape of an orbital: l=0 is s (spherical), l=1 is p (dumbbell), etc.
A. Sodium (Na)
B. Magnesium (Mg)
C. Oxygen (O)
D. Chlorine (Cl)
Answer: Oxygen has an electronegativity of 3.44 on the Pauling scale, which is higher than Na (0.93), Mg (1.31), and Cl (3.16).
A. C6H12O6
B. C6H10O5
C. C12H22O11
D. CH2O
Answer: Glucose is a monosaccharide with the molecular formula C6H12O6, containing six carbon atoms, twelve hydrogen atoms, and six oxygen atoms.
A. Covalent bonding
B. Ionic bonding
C. Metallic bonding
D. Hydrogen bonding
Answer: NaCl is formed by the transfer of an electron from Na to Cl, creating Na+ and Cl- ions held together by electrostatic (ionic) forces.
A. +3
B. +4
C. +6
D. +7
Answer: In K2Cr2O7: 2(+1) + 2(Cr) + 7(-2) = 0, so 2Cr = 12, Cr = +6.
A. Boyle\'s law
B. Charles\'s law
C. Avogadro\'s law
D. Dalton\'s law
Answer: Charles\'s law states V ∝ T (at constant P and n), meaning volume increases linearly with absolute temperature.
A. 1
B. 2
C. 3
D. 4
Answer: HCl is a strong acid that fully dissociates. [H+] = 0.001 M = 10^-3, so pH = -log(10^-3) = 3.
A. Bromine (Br)
B. Chlorine (Cl)
C. Iodine (I)
D. Fluorine (F)
Answer: The configuration [Ar] 3d10 4s2 4p5 has 35 electrons, which corresponds to Bromine (Z = 35).