FBISE Class 9th (SSC-l)

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FBISE Class 9th (SSC-l)

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A. Electron
B. Proton
C. Alpha particle
D. Gamma ray
Answer: In beta minus decay, a neutron converts to a proton, emitting an electron and antineutrino.
A. Charged particles
B. High energy photons
C. Electrons
D. Neutrons
Answer: Gamma rays are high energy electromagnetic photons emitted during nuclear transitions.
A. λ = t½/ln2
B. λ = ln2/t½
C. λ = t½ × ln2
D. λ = 1/t½
Answer: λ = ln2/t½. The decay constant and half-life are inversely related.
A. Becquerel
B. Curie
C. Rutherford
D. All of the above
Answer: Activity can be measured in Becquerel (SI), Curie, or Rutherford units. 1 Ci = 3.7 × 10^10 Bq.
A. p-side to negative, n-side to positive
B. p-side to positive, n-side to negative
C. Both sides to positive
D. Both sides to negative
Answer: Forward bias: p-side connected to positive terminal, n-side to negative, reducing the barrier potential.
A. 0.1 eV
B. 1.1 eV
C. 3.0 eV
D. 5.0 eV
Answer: Silicon has a band gap of about 1.1 eV at room temperature, making it a semiconductor.
A. V₀I₀/2
B. V_rms × I_rms × cos φ
C. V₀I₀
D. V_rms × I_rms
Answer: Average power = V_rms I_rms cos φ, where φ is the phase angle between voltage and current.
A. Maximum
B. Minimum (equal to R)
C. Zero
D. Infinite
Answer: At resonance, XL = XC, so impedance Z = √(R² + (XL-XC)²) = R (minimum value).
A. R/ωL
B. ωL/R
C. 1/RC
D. R/ωC
Answer: Q = ωL/R = 1/(ωCR) at resonance. Higher Q means sharper resonance.
A. 2200 V
B. 220 V
C. 22 V
D. 110 V
Answer: Vs/Vp = Ns/Np → Vs = Vp × (Ns/Np) = 220 × (1/10) = 22 V (step-down transformer).
A. 50%
B. 75%
C. 100%
D. Depends on load
Answer: An ideal transformer has no losses (no copper loss, no iron loss), so efficiency = 100%.
A. Doubles
B. Halves
C. Remains same
D. Quadruples
Answer: Fringe width β = λD/d. If d is halved, β doubles.
A. 1.22λ/D
B. D/(1.22λ)
C. λ/D
D. D/λ
Answer: Resolving power = D/(1.22λ), where D is the aperture diameter and λ is the wavelength of light used.
A. Real and inverted
B. Virtual, erect and magnified
C. Real, erect and magnified
D. Same size as object
Answer: When object is between F and optical center of convex lens, image is virtual, erect, and magnified on the same side.
A. 1 + D/f
B. D/f
C. f/D
D. D/(D+f)
Answer: For a simple microscope (magnifying glass), magnifying power M = 1 + D/f, where D is the least distance of distinct vision.
A. Less than critical angle
B. Equal to critical angle
C. Greater than critical angle
D. 90°
Answer: TIR occurs when angle of incidence > critical angle when light travels from denser to rarer medium.
A. 30°
B. 42°
C. 48.6°
D. 60°
Answer: sin ic = 1/μ = 1/1.5 = 0.667 → ic = sin⁻¹(0.667) ≈ 41.8° ≈ 42°
A. Two isothermal and two adiabatic processes
B. Four isothermal processes
C. Two adiabatic and two isobaric processes
D. Four adiabatic processes
Answer: Carnot cycle: two isothermal (at TH and TL) and two adiabatic processes forming a reversible cycle.
A. 100%
B. Greater than 50%
C. Less than 100%
D. Zero
Answer: Carnot efficiency η = 1 - TL/TH is always less than 100% unless TL = 0 K (impossible).
A. Always decreases
B. Always increases
C. Remains constant
D. Can increase or decrease
Answer: Second law of thermodynamics: entropy of an isolated system always increases or remains constant in reversible processes.