FBISE Class 9th (SSC-l)

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FBISE Class 9th (SSC-l)

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A. C2H2 < C2H4 < C2H6
B. C2H6 < C2H4 < C2H2
C. C2H4 < C2H2 < C2H6
D. C2H2 = C2H4 = C2H6
Answer: Bond length increases as bond order decreases: C-C triple bond (C2H2) < C=C double bond (C2H4) < C-C single bond (C2H6).
A. Methyl orange
B. Alizarin
C. Indigo
D. Aniline yellow
Answer: Alizarin is a mordant dye that requires a metallic mordant (like aluminum hydroxide) to bind to fabric, producing a vivid red color.
A. 180 degrees
B. 120 degrees
C. 104.5 degrees
D. 109.5 degrees
Answer: Water has sp3 hybridization with two bonding pairs and two lone pairs. The lone pair repulsion compresses the H-O-H angle from 109.5 to about 104.5 degrees.
A. HCl < HBr < HI
B. HI < HBr < HCl
C. HCl > HBr > HI
D. HBr < HCl < HI
Answer: Acidic strength of hydrohalic acids increases down the group (HCl < HBr < HI) because bond dissociation energy decreases as atomic size increases.
A. 1 mole
B. 2 moles
C. 0.5 mole
D. 3 moles
Answer: Molar mass of H2O = 18 g/mol. Moles = 36/18 = 2 moles.
A. Geometric isomerism
B. Optical isomerism
C. Linkage isomerism
D. Ionization isomerism
Answer: NO2- is an ambidentate ligand that can bind through N or O. This gives rise to linkage isomerism: -NO2 (nitro) vs -ONO (nitrito).
A. sp3
B. sp2
C. sp
D. sp3d
Answer: BF3 has three bonding pairs and no lone pairs on boron, requiring sp2 hybridization and trigonal planar geometry.
A. KMnO4
B. H2O2
C. Na
D. Cl2
Answer: Sodium (Na) is a strong reducing agent because it readily loses its valence electron to form Na+, getting oxidized in the process.
A. Tetrahedral
B. Square planar
C. See-saw
D. Square pyramidal
Answer: XeF4 has sp3d2 hybridization with 4 bonding pairs and 2 lone pairs. The lone pairs are trans to each other, giving square planar geometry.
A. CH3CH2OH
B. CH3CH(OH)CH3
C. CH3CH(OH)COOH
D. CH3COCH3
Answer: CH3CH(OH)COOH (lactic acid) has a chiral carbon bonded to four different groups (-H, -OH, -CH3, -COOH), exhibiting optical isomerism.
A. 3.74
B. 4.74
C. 5.74
D. 7.00
Answer: pH = pKa + log([salt]/[acid]). When [salt] = [acid], pH = pKa = -log(1.8 x 10^-5) = 4.74.
A. 2s
B. 2p
C. 3s
D. 1s
Answer: In hydrogen (single electron system), energy depends only on n. 3s has n=3, which is higher than n=2 (2s, 2p) and n=1 (1s).
A. KMnO2
B. KMnO3
C. KMnO4
D. K2MnO4
Answer: Potassium permanganate has the formula KMnO4, where Mn is in the +7 oxidation state and is a powerful oxidizing agent.
A. Sodium
B. Iron
C. Silicon
D. Chlorine
Answer: Iron (Fe, Z=26) has partially filled 3d orbitals ([Ar] 3d6 4s2), placing it in the d-block of the periodic table.
A. 0.5 mole
B. 1 mole
C. 2 moles
D. 1.5 moles
Answer: CaCO3 decomposes as: CaCO3 -> CaO + CO2. One mole of CaCO3 produces exactly one mole of CO2.
A. [Ar] 3d9 4s2
B. [Ar] 3d10 4s1
C. [Ar] 3d8 4s2 4p1
D. [Ar] 3d10 4s2
Answer: Copper is an exception to the expected configuration. One 4s electron is promoted to 3d to achieve a fully filled 3d10 subshell for extra stability.
A. H-H
B. O-O
C. H-Cl
D. Na-Cl
Answer: H-Cl has an electronegativity difference of 0.9, resulting in unequal electron sharing (polar covalent bond). Na-Cl is ionic, and H-H and O-O are nonpolar.
A. +1
B. +2
C. +3
D. -2
Answer: Magnesium (Mg) loses its two valence electrons to achieve a stable neon-like configuration, forming Mg2+ with a +2 charge.
A. CH3OH
B. CH3OCH3
C. CH3COOH
D. CH3CHO
Answer: CH3OCH3 (dimethyl ether) has an oxygen atom bonded between two alkyl groups (R-O-R\'), which defines the ether functional group.
A. Positive
B. Negative
C. Zero
D. Variable
Answer: By convention, the standard enthalpy of formation of any element in its most stable standard state is defined as zero.