Unit-14 Hydrocarbons

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Unit-14 Hydrocarbons

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A. Hydrocarbons
B. Carbohydrates
C. Carbonates
D. Hydrates
Answer: Hydrocarbons are organic compounds made up of only carbon and hydrogen atoms.
A. CO2
B. CH4
C. H2O
D. NH3
Answer: Methane (CH4) is a hydrocarbon; the others contain oxygen or nitrogen.
A. CnH2n
B. CnH2n-2
C. CnH2n+2
D. CnHn
Answer: Alkanes follow the general formula CnH2n+2, e.g., methane CH4.
A. C2H6
B. C3H8
C. C4H10
D. CH4
Answer: Methane, the simplest alkane, has the molecular formula CH4.
A. C2H6
B. C2H4
C. CH4
D. C2H2
Answer: Ethane is the second alkane with formula C2H6.
A. C3H6
B. C3H8
C. C2H6
D. C4H10
Answer: Propane has three carbons and follows CnH2n+2, giving C3H8.
A. C4H8
B. C4H6
C. C4H10
D. C3H8
Answer: Butane has four carbons; CnH2n+2 gives C4H10.
A. Methane
B. Propane
C. Butane
D. Ethane
Answer: C2H6 corresponds to ethane.
A. 8
B. 6
C. 4
D. 10
Answer: Propane is C3H8, so it has 8 hydrogen atoms.
A. CH3 unit
B. CH2 unit
C. H2 unit
D. C2H4 unit
Answer: Homologous series members differ by a CH2 group, e.g., CH4, C2H6, C3H8.
A. Solubility
B. Density
C. Chemical affinity
D. Volatility
Answer: Paraffin comes from Latin parum affinis meaning little affinity for other substances.
A. Alkane
B. Alkyne
C. Aromatic
D. Alkene
Answer: Alkenes contain at least one carbon-carbon double bond.
A. CnH2n
B. CnH2n+2
C. CnH2n-2
D. CnHn
Answer: Alkenes follow the general formula CnH2n, e.g., ethene C2H4.
A. C2H2
B. C2H4
C. C2H6
D. CH4
Answer: Ethene is the simplest alkene with the formula C2H4.
A. Ethyne
B. Ethane
C. Ethene
D. Propene
Answer: Ethene (C2H4) is the simplest member of the alkene series.
A. C2H6
B. CH4
C. C3H8
D. C2H4
Answer: C2H4 (ethene) contains a double bond and is therefore unsaturated.
A. Olefins
B. Paraffins
C. Acetylenes
D. Aromatics
Answer: Alkenes are commonly called olefins.
A. C3H4
B. C3H6
C. C3H8
D. C2H4
Answer: Propene follows CnH2n with n=3, giving C3H6.
A. Two sigma bonds
B. Two pi bonds
C. One sigma and one pi bond
D. One pi bond only
Answer: A double bond consists of one sigma and one pi bond.
A. sp3
B. sp
C. None of these
D. sp2
Answer: Alkene double-bond carbons are sp2 hybridized with a trigonal planar shape.
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