Unit-6 Trigonometry and Bearing
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Unit-6 Trigonometry and Bearing
Answer: (1/2)^2 + (sqrt 3 / 2)^2 = 1/4 + 3/4 = 1.
Answer: tan 0 = sin 0 / cos 0 = 0 / 1 = 0.
Answer: The back bearing differs by 180 degrees: 060 + 180 = 240 degrees.
Answer: csc theta = 1 / sin theta.
Answer: One complete revolution equals 2 pi radians.
Answer: (7 pi/6) x (180/pi) = 7 x 30 = 210 degrees.
Answer: 135 x (pi/180) = 135 pi / 180 = 3 pi / 4.
Answer: 90 = 180/2, so 90 degrees = pi/2 radians.
Answer: 1 radian = 180/pi degrees, which is about 57.3 degrees.
Answer: cot theta = 1 / tan theta, so tan theta x cot theta = 1.
Answer: (3 pi/4) x (180/pi) = 135 degrees.
Answer: 360 = 2 x 180, so 360 degrees = 2 pi radians.
Answer: East lies at 090 degrees clockwise from North.
Answer: The back bearing differs by 180 degrees: 315 - 180 = 135 degrees.
Answer: West is 270 degrees clockwise from North.
Answer: sin 90 = 1, the maximum value of sine.
Answer: sin 30 = 1/2.
Answer: cos theta = side adjacent to theta divided by the hypotenuse.
Answer: cos 0 = 1.
Answer: sec 60 = 1 / cos 60 = 1 / (1/2) = 2.