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MCQ
A force of 100 N is applied at 30 degrees to the horizontal and displaces a body through 10 m. The work done is (cos 30 degrees = 0.866):
Unit-6 Work and Energy
A 1000 J
B 500 J
C 866 J
D 5000 J
Explanation

W = F d cos30 = 100 x 10 x 0.866 = 866 J.

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