Home / Unit-6 Trigonometry and Bearing / Question
MCQ
A right triangle has an angle of 30 degrees and a hypotenuse of 10. The side opposite the 30 degree angle is:
Unit-6 Trigonometry and Bearing
A 5
B 10
C 5 sqrt 3
D 10 sqrt 3
Explanation

sin 30 = opposite / 10, so opposite = 10 x (1/2) = 5.

Related MCQs

Evaluate (sin 45)(sec 45):
Unit-6 Trigonometry and Bearing View
Convert 25 degrees 30 minutes to decimal degrees:
Unit-6 Trigonometry and Bearing View
The bearing of B from A is 060 degrees. What is the bearing of A from B?
Unit-6 Trigonometry and Bearing View
Simplify (1 - sin^2 theta)/cos theta:
Unit-6 Trigonometry and Bearing View
csc theta is the reciprocal of which ratio?
Unit-6 Trigonometry and Bearing View
An angle of pi/3 radians measures how many degrees?
Unit-6 Trigonometry and Bearing View