Home / Unit-6 Trigonometry and Bearing / Question
MCQ
tan 30 degrees = ?
Unit-6 Trigonometry and Bearing
A sqrt 3
B 1/2
C 1 / sqrt 3
D 1
Explanation

tan 30 = sin 30 / cos 30 = (1/2) / (sqrt 3 / 2) = 1 / sqrt 3.

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