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MCQ
To double the maximum height of a vertically thrown ball, the initial velocity should be multiplied by:
Unit-2 Kinematics
A sqrt(2) (about 1.41)
B 1/2
C 4
D 2
Explanation

Maximum height h = u^2/(2g) is proportional to u^2, so doubling h requires u to be multiplied by sqrt(2).

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