Unit-7 Coordinate Geometry
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Unit-7 Coordinate Geometry
Answer: A point on the y-axis has x-coordinate 0; only (0, 6) does.
Answer: It is a right triangle with legs 4 and 4, so area = 1/2 x 4 x 4 = 8.
Answer: x is positive and y is negative, which is the fourth quadrant.
Answer: Slope between (1, 1) and (2, 3) is 2 and between (2, 3) and (3, 5) is 2, so the points are collinear.
Answer: The ordinate is the y-coordinate, which is -3.
Answer: All three points of option C satisfy y = x, so they lie on one line.
Answer: The abscissa is the x-coordinate, which is 7.
Answer: Slope of (2, 3) to (4, 7) is 2 and of (4, 7) to (6, 11) is 2, so they are collinear.
Answer: The abscissa is the x-coordinate, which is 5.
Answer: Collinear points give zero area in the triangle area formula.
Answer: The ordinate is the y-coordinate, which is 6.
Answer: d = sqrt((5-2)^2 + (7-3)^2) = sqrt(9 + 16) = sqrt(25) = 5.
Answer: Abscissa 0 means x = 0, so the point is of the form (0, y) on the y-axis.
Answer: d = sqrt((1-(-3))^2 + (-1-4)^2) = sqrt(16 + 25) = sqrt(41).
Answer: The origin lies on both axes and does not belong to any quadrant.
Answer: d = sqrt((-2-1)^2 + (2-(-3))^2) = sqrt(9 + 25) = sqrt(34).
Answer: d = sqrt((2-2)^2 + (4-1)^2) = sqrt(9) = 3.
Answer: d = sqrt((4-(-2))^2 + (-3-1)^2) = sqrt(36 + 16) = sqrt(52).
Answer: d = sqrt((2-5)^2 + (3-3)^2) = sqrt(9) = 3.
Answer: Side lengths are 3, 4 and 5 (a 3-4-5 triangle), so perimeter = 3 + 4 + 5 = 12.