Unit-7 Density and Temperature

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Unit-7 Density and Temperature

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A. 27 g/cm^3
B. 0.27 g/cm^3
C. 270 g/cm^3
D. 2.7 g/cm^3
Answer: Divide kg/m^3 by 1000 to get g/cm^3, so 2700 kg/m^3 = 2.7 g/cm^3.
A. 0 degrees C
B. -4 degrees C
C. 10 degrees C
D. 4 degrees C
Answer: Because water is densest at 4 degrees C, this layer sinks below the colder, lighter water and protects fish.
A. Heat energy
B. Mass
C. Temperature
D. Volume
Answer: Thermal equilibrium means no net heat flow, which happens when temperatures are equal.
A. 200 kg
B. 2000 kg
C. 0.002 kg
D. 500 kg
Answer: Mass = density x volume = 1000 x 2 = 2000 kg.
A. 1.2
B. 12
C. 0.12
D. 120
Answer: Divide kg/m^3 by 1000 to get g/cm^3, so 1200 kg/m^3 = 1.2 g/cm^3.
A. Equal to its real expansion
B. Greater than its real expansion
C. Less than its real expansion
D. Always zero
Answer: The container also expands, so the rise of the liquid level is less than the real expansion of the liquid.
A. Weight of a body
B. Coldness only
C. Size of a body
D. Hotness or coldness
Answer: Temperature indicates how hot or cold a body is.
A. Weight
B. Volume
C. Temperature
D. Relative density
Answer: Rearranging density = mass/volume gives mass = density x volume.
A. Increase
B. Decrease
C. Remain unchanged
D. Become zero
Answer: The whole plate expands uniformly on heating, so the hole also becomes larger.
A. Sink in water
B. Float on water
C. Float half submerged
D. Rise above the surface
Answer: Denser objects sink because their weight exceeds the upthrust of water.
A. Degree Celsius
B. Joule
C. Kelvin
D. Degree Fahrenheit
Answer: The SI unit of temperature is the kelvin (K).
A. 373 K
B. 100 K
C. 273 K
D. 173 K
Answer: K = C + 273 = 100 + 273 = 373 K.
A. 1.00055 m
B. 1.0055 m
C. 1.055 m
D. 0.99945 m
Answer: New length = L0(1 + alpha x temperature change) = 1(1 + 1.1 x 10^-5 x 50) = 1.00055 m.
A. 37 degrees C
B. 98 degrees C
C. 42 degrees C
D. 32 degrees C
Answer: Normal human body temperature is about 37 degrees C, which is 98.6 degrees F.
A. 100 K
B. 373 K
C. 273 K
D. 212 K
Answer: Water boils at 100 degrees C, and K = 100 + 273 = 373 K.
A. 250 K
B. 248 K
C. 273 K
D. 298 K
Answer: K = 25 + 273 = 298 K.
A. 2V
B. 1.09V
C. 0.5V
D. V
Answer: Using V/T = constant with temperatures in kelvin: V2 = V x (327/300) = 1.09V.
A. 0 degrees C
B. -273 K
C. 273 K
D. 0 K
Answer: Absolute zero is 0 K, equal to -273 degrees C, the lowest possible temperature.
A. 37 degrees C
B. 583 degrees C
C. 273 degrees C
D. 103 degrees C
Answer: C = K - 273 = 310 - 273 = 37 degrees C, the normal body temperature.
A. 100 degrees C
B. 212 degrees F
C. 373 K
D. 500 K
Answer: 100 degrees C, 212 degrees F and 373 K are all equal; 500 K equals about 227 degrees C, which is highest.
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